(m+2)(m-2)=m^2+2m-4

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Solution for (m+2)(m-2)=m^2+2m-4 equation: 



(m+2)(m-2)=m^2+2m-4

We move all terms to the left:

(m+2)(m-2)-(m^2+2m-4)=0

We use the square of the difference formula

m^2-(m^2+2m-4)-4=0

We get rid of parentheses

m^2-m^2-2m+4-4=0

We add all the numbers together, and all the variables

-2m=0

m=0/-2

m=0

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